If tan A = cot B, prove that A + B = 90°.
Question.
If tan A = cot B, prove that A + B = 90°.
If tan A = cot B, prove that A + B = 90°.
Solution:
tan A = cot B
tan A = tan (90°–B)
$\therefore \mathrm{A}=90^{\circ}-\mathrm{B}$
A + B = 90°
tan A = cot B
tan A = tan (90°–B)
$\therefore \mathrm{A}=90^{\circ}-\mathrm{B}$
A + B = 90°