If the coordinates of one end of a diameter of a circle are (2, 3) and the coordinates of its centre are (−2, 5),

Question:

If the coordinates of one end of a diameter of a circle are (2, 3) and the coordinates of its centre are (−2, 5), then the coordinates of the other end of the diameter are  

(a) $(-6,7)$

(b) $(6,-7)$

(c) $(4,2)$

(d) $(5,3)$

Solution:

Let (xy) be the coordinates of the other end of the diameter. Then

$-2=\frac{2+x}{2} \Rightarrow x=-6$

$5=\frac{3+y}{2} \Rightarrow y=7$

Hence, the correct answer is option (a).

 

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