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If the plane 2 x-y+2 z+3=0 has the distances


If the plane $2 x-y+2 z+3=0$ has the distances

$\frac{1}{3}$ and $\frac{2}{3}$ units from the planes $4 x-2 y+4 z+\lambda=0$

and $2 x-y+2 z+\mu=0$, respectively, then the maximum value of $\lambda+\mu$ is equal to :

  1. 15

  2. 5

  3. 13

  4. 9

Correct Option: , 3


$4 x-2 y+4 z+6=0$







$\therefore$ Maximum value of $(\mu+\lambda)=13$.

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