# If the standard molar enthalpy

Question:

If the standard molar enthalpy change for combustion of graphite powder is $-2.48 \times 10^{2} \mathrm{~kJ} \mathrm{~mol}^{-1}$, the amount of heat generated on combustion of $1 \mathrm{~g}$ of graphite powder is __________ kJ. (Nearest integer)

Solution:

1 mol graphite $=12 \mathrm{gm} \mathrm{C}$

Ans. $=\frac{248}{12}=20.67 \mathrm{~kJ} / \mathrm{gm}$ heat evolved

Sir
July 11, 2022, 10:35 a.m.