Question:
If the standard molar enthalpy change for combustion of graphite powder is $-2.48 \times 10^{2} \mathrm{~kJ} \mathrm{~mol}^{-1}$, the amount of heat generated on combustion of $1 \mathrm{~g}$ of graphite powder is __________ kJ. (Nearest integer)
Solution:
1 mol graphite $=12 \mathrm{gm} \mathrm{C}$
Ans. $=\frac{248}{12}=20.67 \mathrm{~kJ} / \mathrm{gm}$ heat evolved
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