If the sum of two consecutive numbers

True

Given, one of the consecutive number = x

Then, the next consecutive number = x + 1

According to the question,

$x+x+1=93$

$\Rightarrow$  $2 x=93-1$ [transposing 1 to RHS]

$\Rightarrow \quad 2 x=92$

$\Rightarrow$ $\frac{2 x}{2}=\frac{92}{2}$ [dividing both sides by 2]

$\therefore$ $x=46$

Hence, the other consecutive number $=46+1=47=93-46=93-x$