If the system of equations kx − 5y = 2, 6x + 2y = 7


If the system of equations kx − 5y = 2, 6x + 2y = 7 has no solution, then k =

(a) $-10$

(b) $-5$

(c) $-6$

(d) $-15$


The given systems of equations are

$k x-5 y=2$

$6 x+2 y=7$

If $\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$

Here $a_{1}=k, a_{2}=6, b_{1}=-5, b_{2}=2$




Hence, the correct choice is $d$.

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