Question:
If the system of linear equations
$x-2 y+k z=1$
$2 x+y+z=2$
$3 x-y-k z=3$
has a solution $(x, y, z), z \neq 0$, then $(x, y)$ lies on the straight line whose equation is :
Correct Option: , 3
Solution:
$x-2 y+k z=1$ ............(1)
$2 x+y+z=2$ ..............(2)
$3 x-y-k z=3$ .............(3)
(1) $+(3)$
$\Rightarrow 4 x-3 y=4$
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