If two zeroes of the polynomial x3 + x2 − 9x − 9 are 3 and −3,


If two zeroes of the polynomial $x^{3}+x^{2}-9 x-9$ are 3 and $-3$, then its third zero is

(a) $-1$

(b) 1

(c) $-9$

(d) 9


Let $\alpha=3$ and $\beta=-3$ be the given zeros and $\gamma$ be the third zero of the polynomial $x^{3}+x^{2}-9 x-9$ then

By using $\alpha+\beta+\gamma=\frac{-\text { Coefficient of } x^{2}}{\text { Coefficient of } x^{3}}$



Substituting $\alpha=3$ and $\beta=-3$ in $\alpha+\beta+\gamma=-1$, we get



Hence, the correct choice is $(a)$

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