Question:
In a binary compound, atoms of element $\mathrm{A}$ form a hcp structure and those of element $\mathrm{M}$ occupy $2 / 3$ of the tetrahedral voids of the hcp structure. The formula of the binary compound is :
Correct Option: , 2
Solution:
$\mathbf{M}_{12 \times \frac{2}{3}} \mathrm{~A}_{6}$
$\mathrm{M}_{8} \mathrm{~A}_{6}$
$\mathrm{M}_{4} \mathrm{~A}_{3}$
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