In a cricket tournament 16 school teams participated.

Let the amount received by first place team be a Rs and d be difference in amount

As the difference is same hence the second-place team will receive a – d and the third place a – 2d and so on

The last team receives 275 Rs

As there are 16 teams and all teams are given prizes hence the sequence will have 16 terms because there are 16 teams

Therefore a, a – d, a – 2d… 275

The sequence is in AP with first term as a and common difference is ‘-d’

As the total prize given is of 8000rs hence

a + a – d + a – 2d … + 275 = 8000

The sum of n terms of AP is given by Sn = n/2 (2a + (n – 1) d) where

A is first term and d is common difference

There are 16 terms n = 16 and the sum Sn = 8000

⇒ 8000 = (16/2) (2a + (16 – 1) (-d))

⇒ 8000 = 8(2a – 15d)

⇒ 1000 = 2a – 15d ……1

The last term of AP is 275 and nth term of AP is tn = a + (n – 1) d

The last term is tn = 275

⇒ 275 = a + (16 – 1) (-d)

⇒ 275 = a – 15d ……2

Subtract 2 from 1 that is 1 – 2

⇒ 1000 – 275 = 2a – 15d – a + 15d

⇒ 725 = a

Hence amount received by first place team is Rs.725