In a quadrilateral ABCD, the angles A, B, C and D are in the ratio of 1: 2: 4: 5

Let the angles of the quadrilaterals be

A = x, B = 2x, C = 4x and D = 5x

Then,

A + B + C + D = 360^°

⟹ x + 2x + 4x + 5x = 360^°

⟹ 12x = 360^°

⟹ x = 360°/12

⟹ x = 30^°

Therefore, A = x = 30^°

B = 2x = 60^°

C = 4x = 120^°

D = 5x = 150^°