In a triangle PQR,


In a triangle PQR, the co-ordinates of the points $P$ and $Q$ are $(-2,4)$ and $(4,-2)$ respectively. If the equation of the perpendicular bisector of PR is $2 x-y+2=0$, then the centre of the circumcircle of the $\triangle \mathrm{PQR}$ is :

  1. $(-1,0)$

  2. $(-2,-2)$

  3. $(0,2)$

  4. $(1,4)$

Correct Option: , 2


Solving with $2 x-y+2=0$ will give $(-2,2)$

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