In ΔABC,if BC = AB and ∠B = 80°,


In ΔABC,if BC = AB and ∠B = 80°, then ∠A is equal to

(a) 80°                

(b) 40°                      

(c) 50°                        

(d) 100°



Given, $\triangle A B C$ such that $B C=A B$ and $\angle B=80^{\circ}$

$\ln \triangle A B C$, $A B=B C$

$\Rightarrow \quad \angle C=\angle A$ $\ldots(1)$

[angles opposite to equal sides are equal]

We know that, the sum of all the angles of a triangle is $180^{\circ}$.

$\therefore \quad \angle A+\angle B+\angle C=180^{\circ}$

$\Rightarrow \quad \angle A+80^{\circ}+\angle A=180^{\circ}$

$\Rightarrow \quad 2 \angle A=180^{\circ}-80^{\circ}=100^{\circ}$

$\Rightarrow \quad \angle A=\frac{100^{\circ}}{2}$

$\Rightarrow \quad \angle A=50^{\circ}$

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now