In figure, D and E are two points on BC such that BD = DE = EC. Show that ar(ΔABD) = ar(ΔADE) = ar(ΔAEC).
Question:
In figure, D and E are two points on BC such that BD = DE = EC. Show that ar(ΔABD) = ar(ΔADE) = ar(ΔAEC).
Solution:
Draw a line l through A parallel to BC.
Given that, BD = DE = EC
We observed that the triangles ABD and AEC are on the equal bases and between the same parallels l and BC. Therefore, their areas are equal.
Hence, ar(ΔABD) = ar(ΔADE) = ar(ΔAEC).
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