In figure, It is given that AB = CD and AD = BC. Prove that ΔADC ≅ ΔCBA.

Given that in the figure AB = CD and AD = BC.

We have to prove ΔADC ≅ ΔCBA

Now,

Consider ΔADC and ΔCBA.

We have

AB = CD                     [Given]

BC = AD                     [Given]

And AC = AC             [Common side]

So, by SSS congruence criterion, we have

ΔADC ≅ ΔCBA

Hence proved