In the circle given below,


In the circle given below, let $\mathrm{OA}=1$ unit, $\mathrm{OB}=13$ unit and $\mathrm{PQ} \perp \mathrm{OB}$. Then, the area of the triangle PQB (in square units) is

  1. $24 \sqrt{2}$

  2. $24 \sqrt{3}$

  3. $26 \sqrt{3}$

  4. $26 \sqrt{2}$

Correct Option: , 2



$\mathrm{OA} \cdot \mathrm{AB}$

$=\mathrm{AP} \cdot \mathrm{AQ}$.3

$\Rightarrow 1.12=\lambda . \lambda$

$\Rightarrow \lambda=2 \sqrt{3}$

Area $\triangle \mathrm{PQB}=\frac{1}{2} \times 2 \lambda \times \mathrm{AB}$

$\Delta=\frac{1}{2} \cdot 4 \sqrt{3} \times 12$

$=24 \sqrt{3}$

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now