Question:
In the figure given below DE || BC. If AD = 2.4 cm, DB = 3.6 cm, AC = 5 cm. Find AE.
Solution:
GIVEN: AD = 2.4cm, BD = 3.6cm and AC = 5cm.
TO FIND: AE
According to BASIC PROPORTIONALITY THEOREM If a line is drawn parallel to one side of a triangle intersecting the other two sides, then it divides the two sides in the same ratio.
In ∆ABC, DE || BC.
$\frac{\mathrm{AD}}{\mathrm{AB}}=\frac{\mathrm{AE}}{\mathrm{AC}}$
$\frac{2.4}{2.4+3.6}=\frac{\mathrm{AE}}{\mathrm{AC}}$
$\frac{2.4}{6}=\frac{\mathrm{AE}}{5}$
$\mathrm{AE}=2$
$\mathrm{AE}=2 \mathrm{~cm}$
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