In the given figure, ∠ABC = 69°,

Question. In the given figure, $\angle A B C=69^{\circ}, \angle A C B=31^{\circ}$, find $\angle B D C$.

In the given figure, ∠ABC


In $\triangle A B C$

$\angle B A C+\angle A B C+\angle A C B=180^{\circ}$ (Angle sum property of a triangle)

$\Rightarrow \angle B A C+69^{\circ}+31^{\circ}=180^{\circ}$

$\Rightarrow \angle B A C=180^{\circ}-100^{\circ}$

$\Rightarrow \angle B A C=80^{\circ}$

$\angle B D C=\angle B A C=80^{\circ}$ (Angles in the same segment of a circle are equal)

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