In the given figure,

Question:
In the given figure, a body of mass $M$ is held between two massless springs, on a smooth inclined plane. The free ends of the springs are attached to firm supports. If each spring has spring constant $k$, the frequency of oscillation of given body is :

$\frac{1}{2 \pi} \sqrt{\frac{\mathrm{k}}{2 \mathrm{M}}}$
$\frac{1}{2 \pi} \sqrt{\frac{2 \mathrm{k}}{\mathrm{Mg} \sin \alpha}}$
$\frac{1}{2 \pi} \sqrt{\frac{2 k}{M}}$
$\frac{1}{2 \pi} \sqrt{\frac{\mathrm{k}}{\mathrm{Mg} \sin \alpha}}$

Correct Option: , 3

Solution:

$\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{m}}{\mathrm{K}_{\mathrm{eq}}}}=2 \pi \sqrt{\frac{\mathrm{m}}{2 \mathrm{~K}}}$

$\mathrm{f}=\frac{1}{\mathrm{~T}}=\frac{1}{2 \pi} \sqrt{\frac{2 \mathrm{~K}}{\mathrm{~m}}}$

(Option 3) is correct

In the given figure,

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