Question:
In the given figure, a square OABC is inscribed in a quadrant OPBQ of a circle. If OA = 20 cm, find the area of the shaded region. [Use π = 3.14.]
Solution:
Construction: Join OB
In right triangle AOB
OB2 = OA2 + AB2
= 202 + 202
= 400 + 400
= 800
∴ OB2 = 800
Area of the shaded region = Area of quadrant OPBQ − Area of Square OABC
$=\frac{1}{4} \pi(\mathrm{OB})^{2}-(\mathrm{OA})^{2}$
$=\frac{1}{4} \times 3.14 \times 800-400$
$=628-400$
$=228 \mathrm{~cm}^{2}$
Hence, the area of the shaded region is 228 cm2.
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