In the given figure, each of PA, QB, RC and SD is perpendicular to l.
In the given figure, each of PA, QB, RC and SD is perpendicular to l. If AB = 6 cm, BC = 9 cm, CD = 12 cm and PS = 36 cm, then determine PQ, QR and RS.

Given $A B=6 \mathrm{~cm}, B C=9 \mathrm{~cm}, C D=12 \mathrm{~cm}, A D=27 \mathrm{~cm}$ and $P S=36 \mathrm{~cm}$
PA, QB, RC and SD is perpendicular to l,

Therefore, by the corollory of basic proportionality theorem, we have
$\frac{A B}{A D}=\frac{P Q}{P S}$
$\frac{B C}{A D}=\frac{Q R}{P S}$
$\frac{C D}{A D}=\frac{R S}{P S}$
$\Rightarrow \frac{A B}{A D}=\frac{P Q}{P S}$
$\frac{6}{27}=\frac{P Q}{36}$
$\frac{6 \times 36}{27}=P Q$
$P Q=8$
Now for QR
$\frac{B C}{A D}=\frac{Q R}{P S}$
$\frac{9}{27}=\frac{Q R}{36}$
$\frac{9 \times 36}{27}=Q R$
$Q R=12$
Again for RS
$\frac{C D}{A D}=\frac{R S}{P S}$
$\frac{12}{27}=\frac{R S}{36}$
$\frac{12 \times 36}{27}=R S$
$R S=16$
Hence, the values of $P Q, Q R$ and $R S$ are $8,12,16$ respectively.