It is known that a box of 100 electric bulbs contains 8 defective bulbs.

Question:

It is known that a box of 100 electric bulbs contains 8 defective bulbs. One bulb is taken out at random from the box. What is the probability that the bulb drawn is

(i) defective?

(ii) non-defective?

Solution:

Total number of bulbs in the box $=100$

(i) Number of defective bulbs $=8$

$\therefore \mathrm{P}_{(\text {defective bulb })}=\frac{8}{100}=\frac{2}{25}$

(ii) Number of functioning bulbs $=100-8=92$

$\therefore \mathrm{P}_{(\text {non-defective } \text { bulb })}=\frac{92}{100}=\frac{23}{25}$

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