Let abc be a three-digit number.


Let abc be a three-digit number. Then, abc + bca + cab is not divisible by

(a) a + b + c

(b) 3

(c) 37

(d) 9


(d) We know that, the sum of three-digit numbers taken in cyclic order can be written as 111 (a + b + c).

i.e. abc + pea + cab = 3 x 37 x (a + b + c)

Hence, the sum is divisible by 3, 37 and (a + b + c) but not divisible by 9.

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