Let C1 and C2 be the centres of the circles


let $C_{1}$ and $C_{2}$ be the centres of the circles $x^{2}+y^{2}-2 x-2 y-2=0$ and $x^{2}+y^{2}-6 x-6 y+14=0$ respectively. If $P$ and $Q$ are the points of intersection of these circles, then the area (in sq. units) of the quadrilateral $\mathrm{PC}_{1} \mathrm{QC}_{2}$ is :

  1. 8

  2. 6

  3. 9

  4. 4

Correct Option: , 4


Area $=2 \times \frac{1}{2} \cdot 4=2$

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now