Question:
Let $f: R \rightarrow R$ and $g: R \rightarrow R$ be defined by $f(x)=x^{2}$ and $g(x)=x+1$. Show that fog $\neq g$ of.
Solution:
Given, $f: R \rightarrow R$ and $g: R \rightarrow R$.
So, the domains of $f$ and $g$ are the same.
$(f o g)(x)=f(g(x))=f(x+1)=(x+1)^{2}=x^{2}+1+2 x$
$(g o f)(x)=g(f(x))=g\left(x^{2}\right)=x^{2}+1$
So, fog ≠ gof
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