Let f: R → R be defined as f(x)


Let fR → R be defined as f(x)

(A) $f$ is one-one onto (B) $f$ is many-one onto

(C) $f$ is one-one but not onto (D) $f$ is neither one-one nor onto


$f: \mathbf{R} \rightarrow \mathbf{R}$ is defined as $f(x)=3 x$.

Let $x, y \in \mathbf{R}$ such that $f(x)=f(y)$.

$\Rightarrow 3 x=3 y$

$\Rightarrow x=y$

is one-one.

Also, for any real number $(y)$ in co-domain $\mathbf{R}$, there exists $\frac{y}{3}$ in $\mathbf{R}$ such that $f\left(\frac{y}{3}\right)=3\left(\frac{y}{3}\right)=y$.

is onto.

Hence, function f is one-one and onto.

The correct answer is A.

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