Let I be an identity matrix of order 2X2 and

Question:

Let $I$ be an identity matrix of order $2 \times 2$ and

$P=\left[\begin{array}{rr}2 & -1 \\ 5 & -3\end{array}\right] .$ Then the value of $n \in N$ for

which $\mathrm{Pn}=5 \mathrm{I}-8 \mathrm{P}$ is equal to__________

Solution:

$P=\left[\begin{array}{ll}2 & -1 \\ 5 & -3\end{array}\right]$

$5 \mathrm{I}-8 \mathrm{P}=\left[\begin{array}{ll}5 & 0 \\ 0 & 5\end{array}\right]-\left[\begin{array}{cc}16 & -8 \\ 40 & -24\end{array}\right]=\left[\begin{array}{cc}-11 & 8 \\ -40 & 29\end{array}\right]$

$\mathrm{P}^{2}=\left[\begin{array}{ll}-1 & 1 \\ -5 & 4\end{array}\right]$

$\mathrm{P}^{3}=\left[\begin{array}{cc}3 & -2 \\ 10 & -7\end{array}\right] \Rightarrow \mathrm{P}^{6}=\left[\begin{array}{cc}-11 & 8 \\ -40 & 29\end{array}\right]=\mathrm{P}^{\mathrm{n}}$

$\Rightarrow \mathrm{n}=6$

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