Let the position vectors of two points


Let the position vectors of two points $\mathrm{P}$ and $\mathrm{Q}$

be $3 \hat{\mathrm{i}}-\hat{\mathrm{j}}+2 \hat{\mathrm{k}}$ and $\hat{\mathrm{i}}+2 \hat{\mathrm{j}}-4 \hat{\mathrm{k}}$, respectively. LetR and $\mathrm{S}$ be two points such that the direction ratios of lines $\mathrm{PR}$ and $\mathrm{QS}$ are $(4,-1,2)$ and $(-2,1,-2)$, respectively. Let lines $\mathrm{PR}$ andQS intersect at $\mathrm{T}$. If the vector $\overrightarrow{\mathrm{TA}}$ is perpendicular to both $\overrightarrow{\mathrm{PR}}$ and $\overrightarrow{\mathrm{QS}}$ and thelength of vector $\overrightarrow{\mathrm{TA}}$ is $\sqrt{5}$ units, then the

modulus of a position vector of $\mathrm{A}$ is :

  1. (1) $\sqrt{482}$

  2. (2) $\sqrt{171}$

  3. (3) $\sqrt{5}$

  4. (4) $\sqrt{227}$

Correct Option: 2,




$\overrightarrow{\mathrm{PR}} \| 4 \hat{\mathrm{i}}-\hat{\mathrm{j}}+2 \hat{\mathrm{k}}$

$\overrightarrow{\mathrm{QS}} \|-2 \hat{\mathrm{i}}+\hat{\mathrm{j}}-2 \hat{\mathrm{k}}$

dr's of normal to the plane containing

$\mathrm{P}, \mathrm{T} \& \mathrm{Q}$ will be proportional to

$\left|\begin{array}{ccc}\hat{\mathrm{i}} & \hat{\mathrm{j}} & \hat{\mathrm{k}} \\ 4 & -1 & 2 \\ -2 & 1 & -2\end{array}\right|$

$\therefore \quad \frac{\ell}{0}=\frac{\mathrm{m}}{4}=\frac{\mathrm{n}}{2}$

For point, $\mathrm{T}: \overrightarrow{\mathrm{PT}}=\frac{\mathrm{x}-3}{4}=\frac{\mathrm{y}+1}{-1}=\frac{\mathrm{z}-2}{2}=\lambda$


$\mathrm{T}:(4 \lambda+3,-\lambda-1,2 \lambda+2)$

$\cong(2 \mu+1, \mu+2,-2 \mu-4)$

$4 \lambda+3=-2 \mu+1 \quad \Rightarrow 2 \lambda+\mu=-1$

$\lambda+\mu=-3 \quad \Rightarrow \quad \lambda=2$

$\& \quad \mu=-5 \quad \lambda+\mu=-3 \quad \Rightarrow \quad \lambda=2$

So point $T:(11,-3,6)$

$\overrightarrow{\mathrm{OA}}=(11 \hat{\mathrm{i}}-3 \hat{\mathrm{j}}+6 \hat{\mathrm{k}}) \pm\left(\frac{2 \hat{\mathrm{j}}+\hat{\mathrm{k}}}{\sqrt{5}}\right) \sqrt{5}$

$\overrightarrow{O A}=(11 \hat{i}-3 \hat{i}+6 \hat{k})+(2 \hat{i}+\hat{k})$

$\overrightarrow{\mathrm{OA}}=11 \hat{\mathrm{i}}-\hat{\mathrm{j}}+7 \hat{\mathrm{k}}$


$9 \hat{\mathrm{i}}-5 \hat{\mathrm{j}}+5 \hat{\mathrm{k}}$






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