Question:
Making use of the cube root table, find the cube root
833
Solution:
We have:
$830<833<840 \Rightarrow \sqrt[3]{830}<\sqrt[3]{833}<\sqrt[3]{840}$
From the cube root table, we have:
$\sqrt[3]{830}=9.398$ and $\sqrt[3]{840}=9.435$
For the difference $(840-830)$, i.e., 10 , the difference in values
$=9.435-9.398=0.037$
$\therefore$ For the difference $(833-830)$, i.e., 3 , the difference in values
$=\frac{0.037}{10} \times 3=0.0111=0.011$ (upto three decimal places)
$\therefore \sqrt[3]{833}=9.398+0.011=9.409$
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