Mark (✓) against the correct answer:


Mark (✓) against the correct answer:

If the compound interest on a certain sum for 2 years at 10% per annum is Rs 1050, the sum is

(a) Rs 3000

(b) Rs 4000

(c) Rs 5000

(d) Rs 6000


(c) Rs 5000

Here, $A=P \times\left(1+\frac{R}{100}\right)^{n}$

$=P \times\left(1+\frac{10}{100}\right)^{2}$

$=P \times\left(\frac{110}{100}\right)^{2}$

$=P \times\left(\frac{11}{10}\right) \times\left(\frac{11}{10}\right)$

Now, $C I=A-P$

$\Rightarrow$ Rs. $1050=\frac{121 p}{100}-P$

$=\frac{121 P-100 P}{100}$

$=\frac{21 P}{100}$

$\therefore P=\mathrm{Rs} \frac{1050 \times 100}{21}=\mathrm{Rs} 5000$



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