Mark against the correct answer in the following:
Question:

Mark $(\sqrt{)}$ against the correct answer in the following:

The general solution of the $D E \frac{d y}{d x}=\left(\sqrt{1-x^{2}}\right)\left(\sqrt{1-y^{2}}\right)$ is

A. $\sin ^{-1} y-\sin ^{-1} x=x \sqrt{1-x^{2}}+C$

B. $2 \sin ^{-1} y-\sin ^{-1} x=x \sqrt{1-x^{2}}+C$

C. $2 \sin ^{-1} y-\sin ^{-1} x=C$

D. None of these

Solution:

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