Match each of the sets on the left described in the roster from with the same
Match each of the sets on the left described in the roster from with the same
set on the right described in the set-builder from:

(i) {-5, 5}
It can be seen that if we take the square of -5 and 5, the result will be 25
If $x=-5$, then $(-5)^{2}=25$
If $x=5$, then $(5)^{2}=25$
and -5, 5 both are integers
So, $\left\{x: x \in Z\right.$ and $\left.x^{2}=25\right\}$
$\therefore$ (i) matches (c)
(ii) $\{1,2,3,6,9,18\}$
Divisor of 18 are
$18=18 \times 1$
$18=9 \times 2$
$18=6 \times 3$
1, 2, 3, 6, 9, 18 are divisors of 18
So, {x : x ∈ N and x is a factor of 18}
$\therefore$ (ii) matches (d)
(iii) $\{-3,-2,-1,0,1,2,3\}$
$(-3)^{2}=9<16$
$(-2)^{2}=4<16$
$(-1)^{2}=1<16$
$(0)^{2}=0<16$
$(1)^{2}=1<16$
$(2)^{2}=4<16$
$(3)^{2}=9<16$
All are the given elements are integers and satisfying x2 < 16
So, (iii) matches (a)
(iv) $\{\mathrm{P}, \mathrm{R}, \mathrm{I}, \mathrm{N}, \mathrm{C}, \mathrm{A}, \mathrm{L}\}$
There are 9 letters in the word PRINCIPAL out of which P and I are repeated.
So, {x : x is a letter in the word ‘PRINCIPAL’}
$\therefore$ (iv) matches (e)
(v) $\{1\}$
Since, $1 \in N$ and $(1)^{2}=1$
So, $\left\{x: x \in N\right.$ and $\left.x^{2}=x\right\}$
$\therefore$ (v) matches (b)
