Question:
Match the complex ions given in Column I with the hybridisation and number
of unpaired electrons given in Column II and assign the correct code :
Code :
(i) A (3) B (1) C (5) D (2)
(ii) A (4) B (3) C (2) D (1)
(iii) A (3) B (2) C (4) D (1)
(iv) A (4) B (1) C (2) D (3)
Solution:
Option (i) A (3) B (1) C (5) D (2) is the answer
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.