MnO42- undergoes disproportionation


 MnO42- undergoes disproportionation reaction in acidic medium but MnO4–

does not. Give reason.


In – MnO4, Mn is in the highest oxidation state i.e. +7. Therefore, it does

not undergo disproportionation. MnO42– undergoes disproportionation

as follows :

3MnO42– + 4H+ → 2MnO4– + MnO2+ 2H2O

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