**Question:**

Look at the adjoining figure. Show that length AH > sum of lengths of AB + BC+CD.

Thinking Process

Apply the Euclid’s axiom, the whole is greater than the part, to show the given result.

**Solution:**

From the given figure, we have

AB+ BC + CD = AD [AB, SC and CD are the parts of AD] Here, AD is also the parts of AH.

According to Euclid’s axiom, the whole is greater than the part. i.e., AH> AD.

So, length AH> sum of lengths of AB+ BC + CD.