On comparing the ratios $\frac{\mathbf{a}_{1}}{\mathbf{a}_{8}}, \frac{\mathbf{b}_{1}}{\mathbf{b}_{2}}$ and $\frac{\mathbf{c}_{1}}{\mathbf{c}_{2}}$, find out whether the lines representing the

Solution:

(i) $5 x-4 y+8=0$ ...(i)

$7 x+6 y-9=0$ ...(ii)

$\frac{a_{1}}{a_{2}}=\frac{5}{7}, \frac{h_{1}}{b_{2}}=\frac{-4}{6}=-\frac{2}{3} \quad \Rightarrow \frac{a_{1}}{a_{2}} \neq \frac{b_{1}}{b_{2}}$

 Lines represented by (i) and (ii) intersect at a point

(ii) $9 x+3 y+12=0$ ...(i)

$18 x+6 y+24=0$ ...(ii)

$\frac{a_{1}}{a_{2}}=\frac{9}{18}, \frac{b_{1}}{b_{2}}=\frac{3}{6}, \frac{c_{1}}{c_{2}}=\frac{12}{24}$

$\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$

 Lines represented by (i) and (ii) are coincident

(iii) $6 x-3 y+10=0$ ...(i)

$2 x-y+9=0$ ...(ii)

$\frac{a_{1}}{a_{2}}=\frac{6}{2}=\frac{3}{1}, \frac{b_{1}}{b_{2}}=\frac{-3}{-1}=\frac{3}{1}, \frac{c_{1}}{c_{2}}=\frac{10}{9}$

$\Rightarrow \frac{\mathbf{a}_{1}}{\mathbf{a}_{2}}=\frac{\mathbf{b}_{1}}{\mathbf{b}_{2}} \neq \frac{\mathbf{c}_{1}}{\mathbf{c}_{2}}$

 Lines represented by (i) and (ii) are parallel