# Oxidation number of potassium in

Question:

Oxidation number of potassium in $\mathrm{K}_{2} \mathrm{O}, \mathrm{K}_{2} \mathrm{O}_{2}$ and $\mathrm{KO}_{2}$, respectively, is:

1. $+2,+1$ and $+\frac{1}{2}$

2. $+1,+1$ and $+1$

3. $+1,+4$ and $+2$

4. $+1,+2$ and $+4$

Correct Option: , 2

Solution:

$\mathrm{K}_{2} \mathrm{O}: 2 x-2=0 \Rightarrow x=+1$

$\mathrm{~K}_{2} \mathrm{O}_{2}: 2 x-2=0 \Rightarrow x=+1$

$\mathrm{KO}_{2}: x-1=0 \Rightarrow x=+1$

Thus, potassium shows $+1$ state in all its oxides, superoxides and peroxides.