Paheli prepared a blue coloured solution of copper sulphate in beaker A and placed an iron nail in it. Boojho prepared a yellowish green
solution of ferrous sulphate in beaker B and placed a copper wire in it. What changes will they observe in the two beakers after an hour?
In beaker A1, a reddish brown layer of copper will deposit on the iron nail and blue coloured solution of copper sulphate will become yellowish green
due to the formation of iron sulphate. This is because iron is more reactive than copper and it displaces copper from its salt solution (copper
sulphate solution). In beaker B1, no change is observed because copper being less reactive does not displace iron (more reactive) from ferrous
sulphate solution.
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