Question:
Potassium chlorate is prepared by the electrolysis of $\mathrm{KCl}$ in basic solution
$6 \mathrm{OH}^{-}+\mathrm{Cl}^{-} \rightarrow \mathrm{ClO}_{3}^{-}+3 \mathrm{H}_{2} \mathrm{O}+6 \mathrm{e}^{-}$
If only $60 \%$ of the current is utilized in the reaction, the time (rounded to the nearest hour) required to produce $10 \mathrm{~g}$ of $\mathrm{KCIO}_{3}$ using a current of $2 \mathrm{~A}$ is_____.
(Given : $\mathrm{F}=96,500 \mathrm{C} \mathrm{mol}^{-1}$ molar mass of $\left.\mathrm{KClO}_{3}=122 \mathrm{gmol}^{-1}\right)$
Solution:
Official Ans. by NTA (11.00)
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