PQR is a triangle in which PQ = PR and is any point on the side PQ.

Question:

PQR is a triangle in which PQ = PR and is any point on the side PQ. Through S, a line is drawn parallel to QR and intersecting PR at T. Prove that PS = PT.

Solution:

Given that PQR is a triangle such that PQ = PR ant S is any point on the side PQ and ST ∥ QR.

To Prove,

PS = PT

Since, PQ = PR

PQR is an isosceles triangle.

∠Q = ∠R (or) ∠PQR = ∠PRQ

Now, ∠PST = ∠PQR and ∠PTS = ∠PRQ [Corresponding angles as ST parallel to QR]

Since, ∠PQR = ∠PRQ

∠PST = ∠PTS

Now, In ΔPST, ∠PST = ∠PTS

ΔPST is an isosceles triangle

Therefore, PS = PT

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