Pressure inside two soap bubbles are 1.01
Question:

Pressure inside two soap bubbles are $1.01$ and $1.02$ atmosphere, respectively. The ratio of their volumes is :

  1. $8: 1$

  2. $0.8: 1$

  3. $2: 1$

  4. $4: 1$


Correct Option: 1

Solution:

$\mathrm{P}_{1}=0.01=4 \mathrm{~T} / \mathrm{R}_{1}$…………(1)

$\mathrm{P}_{2}=0.02=4 \mathrm{~T} / \mathrm{R}_{2}$……….(2)

Equation (1) . (2)

$\frac{1}{2}=\frac{\mathrm{R}_{2}}{\mathrm{R}_{1}}$

$\mathrm{R}_{1}=2 \mathrm{R}_{2}$

$\frac{V_{1}}{V_{2}}=\frac{R_{1}^{3}}{R_{2}^{3}}=\frac{8 R_{2}^{3}}{R_{2}^{3}}=8$

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