Question:
Product of the following monomials 4p, – 7q3, –7pq is
(a) 196 p2q4
(b) 196 pq4
(c) – 196 p2q4
(d) 196 p2q3
Solution:
(a) 196 p2q4
= 4p × (– 7q3) × (–7pq)
= (4 × (-7) × (-7)) × p × q3 × pq
= 196p2q4
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