Question:
$\sin x \cdot \sin (\cos x)$
Solution:
$\sin x \cdot \sin (\cos x)$
Let $\cos x=t$
$\therefore-\sin x d x=d t$
$\Rightarrow \int \sin x \cdot \sin (\cos x) d x=-\int \sin t d t$
$=-[-\cos t]+C$
$=\cos t+C$
$=\cos (\cos x)+C$
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