Question:
$\frac{3 x^{2}}{x^{6}+1}$
Solution:
Let $x^{3}=t$
$\therefore 3 x^{2} d x=d t$
$\Rightarrow \int \frac{3 x^{2}}{x^{6}+1} d x=\int \frac{d t}{t^{2}+1}$
$=\tan ^{1} t+C$
$=\tan ^{-1}\left(x^{3}\right)+C$
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