Prove the following

Question:

$\lim _{x \rightarrow 0} \frac{\sin ^{2}\left(\pi \cos ^{4} x\right)}{x^{4}}$ is equal to :

  1. $\pi^{2}$

  2. $2 \pi^{2}$

  3. $4 \pi^{2}$

  4. $4 \pi$


Correct Option: , 3

Solution:

$\lim _{x \rightarrow 0} \frac{\sin ^{2}\left(\pi \cos ^{4} x\right)}{x^{4}}$

$\lim _{x \rightarrow 0} \frac{1-\cos \left(2 \pi \cos ^{4} x\right)}{2 x^{4}}$

$\lim _{x \rightarrow 0} \frac{1-\cos \left(2 \pi-2 \pi \cos ^{4} x\right)}{\left[2 \pi\left(1-\cos ^{4} x\right)\right]^{2}} 4 \pi^{2} \cdot \frac{\sin ^{4} x}{2 x^{4}}\left(1+\cos ^{2} x\right)^{2}$

$=\frac{1}{2} \cdot 4 \pi^{2} \cdot \frac{1}{2}(2)^{2}=4 \pi^{2}$

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