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Prove the following

Question:

Suppose

$\vec{a}$ is a vector of magnitude $4.5$ unit due north. What is the vector

(a) $3 \vec{a}$

(b) $-4 \vec{a}$ ?

Solution:

$a=4.5 \mathbf{n}$, where $\mathbf{n}$ is unit vector in north direction

(a) $3 a=4.5 \times 3 n=13.5$ in north direction

(b) $-4 a=4.5 X-4 n=18$ in south direction