Prove the following

Question:

Two capacitors $\mathrm{C}_{1}$ and $\mathrm{C}_{2}$ are charged to $120 \mathrm{~V}$ and $200 \mathrm{~V}$ respectively. It is found that by connecting them together the potential on each one can be made zero. Then :

  1. $5 \mathrm{C}_{1}=3 \mathrm{C}_{2}$

  2. $3 \mathrm{C}_{1}=5 \mathrm{C}_{2}$

  3. $3 \mathrm{C}_{1}+5 \mathrm{C}_{2}=0$

  4.  $9 C_{1}=4 C_{2}$


Correct Option: , 2

Solution:

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