Ravish wanted to make a temporary shelter for his car by making a box-like structure with the tarpaulin that covers all the four sides and the top of the car ( with the front face of a flap which can be rolled up).
Question:

Ravish wanted to make a temporary shelter for his car by making a box-like structure with the tarpaulin that covers all the four sides and the top of the car ( with the front face of a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how many tarpaulins would be required to make the shelter of height 2.5 m with base dimensions 4 m × 3m?

Solution:

Given That,

Shelter length = 4 m

Breadth = 3 m

Height = 2.5 m

The tarpaulin will be required for top and four sides of the shelter.

The Area of tarpaulin required = 2h(l + b) + lb

⇒ 2∗2.5 (4 + 3) + 4∗3

⇒ 5(7) + 12

$\Rightarrow 47 \mathrm{~m}^{2}$

 

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