Solve 24x < 100,

Question:

Solve 24x < 100, when

(i) x is a natural number

(ii) $x$ is an integer

Solution:

The given inequality is $24 x<100$.

$24 x<100$

$\Rightarrow \frac{24 x}{24}<\frac{100}{24}$ [Dividing both sides by same positive number]

(i) It is evident that $1,2,3$, and 4 are the only natural numbers less than $\frac{25}{6}$

Thus, when x is a natural number, the solutions of the given inequality are 1, 2, 3, and 4.

Hence, in this case, the solution set is {1, 2, 3, 4}.

(ii) The integers less than $\frac{25}{6}$ are ...-3, $-2,-1,0,1,2,3,4$.

Thus, when x is an integer, the solutions of the given inequality are

…–3, –2, –1, 0, 1, 2, 3, 4.

Hence, in this case, the solution set is {…–3, –2, –1, 0, 1, 2, 3, 4}.

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