Question:
Solve each of the following systems of equations by the method of cross-multiplication :
$3 x+2 y+25=0$
$2 x+y+10=0$
Solution:
GIVEN:
$3 x+2 y+25=0$
$2 x+y+10=0$
To find: The solution of the systems of equation by the method of cross-multiplication:
By cross multiplication method we get
Also $y=\frac{20}{-1}$
Hence we get the value of $x=5$ and $y=-20$
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